시간 제한메모리 제한제출정답맞힌 사람정답 비율
1 초 256 MB60838029165.393%

문제

존 폰 노이만은 1946년에 유사난수(Pseudo-random Number) 수열을 만드는 방법을 제시했다. 이 방법은 "middle-square" 방법으로 알려져 있으며, 다음과 같이 동작한다.

먼저, 초기값 a0을 고른다. a0은 십진법으로 표기했을 때, 길이가 n을 넘지 않아야 한다. 그 다음, a0을 제곱한 다음에, 길이가 2*n이 될 때 까지 앞에 0을 붙인다. 이제, 가운데 n자리를 ai라고 한다. 이 방법을 사용해 각각의 i>0에 대해서, ai를 계산할 수 있다. 이 문제에서 n=4를 이용한다.

예 1: a0 = 5555, a02 = 30858025, a1 = 8580

예 2: a0 = 1111, a02 = 01234321, a1 = 2343

사실 이 방법은 난수를 만드는데 그렇게 좋은 방법은 아니다. 

a0이 주어졌을 때, 서로 다른 난수를 몇 개 만드는지 구하는 프로그램을 작성하시오.

입력

입력은 여러 개의 테스트 케이스로 이루어져 있다. 각 테스트 케이스는 한 줄이며, a0을 포함하고 있다. (0 < a0 < 10000) 숫자가 네 자리가 아닌 경우에는, 앞에 0을 추가해 네 자리로 만들어져 있다. 입력의 마지막 줄에는 0이 하나 주어진다.

출력

각 테스트 케이스에 대해서, 서로 다른 ai가 몇 개 나오는지 출력한다. a0도 포함해서 세야 한다.

예제 입력 1

5555
0815
6239
0

예제 출력 1

32
17
111
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

출처

Contest > University of Ulm Local Contest > University of Ulm Local Contest 2009 G번

  • 문제의 오타를 찾은 사람: 10_J
  • 문제를 번역한 사람: baekjoon